The basic thought is to count the points that have the same slope to every point. Also do not miss the vertical lines.
Solution:
# T:O(n^2) S:O(n)
class Solution:
# @param points, a list of Points
# @return an integer
def maxPoints(self, points):
max_points = 0
for i, start in enumerate(points):
slope_count, same = {}, 1
for j in xrange(i + 1, len(points)):
end = points[j]
if start.x == end.x and start.y == end.y:
same += 1
else:
slope = float("inf")
if start.x - end.x != 0:
slope = (start.y - end.y) * 1.0 / (start.x - end.x)
if slope not in slope_count:
slope_count[slope] = 1
else:
slope_count[slope] += 1
current_max = same
for slope in slope_count:
current_max = max(current_max, slope_count[slope] + same)
max_points = max(max_points, current_max)
return max_points
Run Time: 80 ms
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