Note that a very small negative number can be very large after timing a negative number, so the min value should also be recorded.
Solution:
# T:O(n) S:O(1) class Solution: # @param A, a list of integers # @return an integer def maxProduct(self, A): global_max, local_max, local_min = float("-inf"), 1, 1 for x in A: local_max, local_min = max(x, local_max * x, local_min * x), min(x, local_max * x, local_min * x) global_max = max(global_max, local_max) return global_maxRun Time: 84 ms
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