# Time: O(m + n) # Space: O(1) # # Given two strings S and T, determine if they are both one edit distance apart. # class Solution: # @param s, a string # @param t, a string # @return a boolean def isOneEditDistance(self, s, t): m, n = len(s), len(t) if m > n: return self.isOneEditDistance(t, s) if n - m > 1: return False i, shift = 0, n - m while i < m and s[i] == t[i]: i += 1 if shift == 0: i += 1 while i < m and s[i] == t[i + shift]: i += 1 return i == m
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