Easy problem. Just try to record min price and see if now is the best time to sell.
Solution:
# T:O(n) S:O(1)
class Solution:
# @param prices, a list of integer
# @return an integer
def maxProfit(self, prices):
max_profit, min_price = 0, float("inf")
for price in prices:
min_price = min(min_price, price)
max_profit = max(max_profit, price - min_price)
return max_profit
Run Time: 72 ms
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