DFS, while we need to cut the repeat branches.
Solution:
# T:O(n!) S:O(n)
class Solution:
# @param num, a list of integer
# @return a list of lists of integers
def permuteUnique(self, num):
length = len(num)
if length == 0: return []
if length == 1: return [num]
num.sort()
res = []
previousNum = None
for i in range(length):
if num[i] == previousNum: continue
previousNum = num[i]
for j in self.permuteUnique(num[:i] + num[i+1:]):
res.append([num[i]] + j)
return res
Run Time: 132 ms
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